11254 - Consecutive Integers
Solution Description : Mathematics problem Input: sum We know sum = n/2 {2a+(n-1)*d } Here, d=1 so, 2*sum = n (2a+n-1) => a = (2*sum + n - n^2)/2n If you can find the value of n (n is maximum is possible) then the ans are a and (a+n-1) maximum n can be sqrt(2*sum) For find a, if 2*sum+n-n^2 is divisible by 2*n (Here n from sqrt(2*sum) to 1) use long long for calculation. |
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