10310 - Dog and Gopher

Difficulty : easy

Solution Description :

Geometry problem

Take the dog(dx, dy) and gopher(gx, gy) coordinates in, and for each point (x, y) that you get:

gopherDis =  sqrt((gx-x)^2 + (gy-y)^2))
dogDis = sqrt((dx-x)^2 + (dy-y)^2) 
if twice of gopher distance is less or equal dog distance then
    output "he escapes"
else
    otherwise, he doesn't.

Remember you need to find the minimum distance escape hole coordinate (x,y)