11068 - An Easy Task
Solution Description : Geometry Line Problem You need to find intersection point from two line equation. If the two line equation are a1X + b1Y = C1 ------------------------------ a2X + b2Y = C2 ------------------------------ From equation (i) you get Y = (c1 - a1X) / b1 ------------------------------ From equation (ii) you get Y = (c2 - a2X)/ b2 ------------------------------ So, =>(c1 - a1X) / b1 = (c2 - a2X)/ b2 =>(c1 - a1X) *b2 = (c2 - a2X) * b1 => X = (b1c2 - b2c1) / (a2b1 - a1b2) ---------(v) From equation (v) you get the value of X And put the value of X to equation (iii) you got the value of Y Print X and Y Remember that if (a2b1 - a1b2)==0 then print No fixed point exists. |
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